some apps
Solve the following and check with the
answers given at the end.
1. It was calculated that 75 men could complete
a piece of work in 20 days. When work was scheduled
to commence, it was found necessary to send 25
men to another project. How much longer will it
take to complete the work?
2. A student divided a number by 2/3 when he
required to multiply by 3/2. Calculate the percentage
of error in his result.
3. A dishonest shopkeeper professes to sell pulses
at the cost price, but he uses a false weight
of 950gm. for a kg. His gain is …%.
4. A software engineer has the capability of
thinking 100 lines of code in five minutes and
can type 100 lines of code in 10 minutes. He takes
a break for five minutes after every ten minutes.
How many lines of codes will he complete typing
after an hour?
5. A man was engaged on a job for 30 days on
the condition that he would get a wage of Rs.
10 for the day he works, but he have to pay a
fine of Rs. 2 for each day of his absence. If
he gets Rs. 216 at the end, he was absent for
work for ... days.
6. A contractor agreeing to finish a work in
150 days, employed 75 men each working 8 hours
daily. After 90 days, only 2/7 of the work was
completed. Increasing the number of men by ________
each working now for 10 hours daily, the work
can be completed in time.
7. what is a percent of b divided by b percent
of a?
(a) a (b) b (c) 1 (d) 10 (d) 100
8. A man bought a horse and a cart. If he sold
the horse at 10 % loss and the cart at 20 % gain,
he would not lose anything; but if he sold the
horse at 5% loss and the cart at 5% gain, he would
lose Rs. 10 in the bargain. The amount paid by
him was Rs._______ for the horse and Rs.________
for the cart.
9.If a light flashes every 6 seconds, how many
times will it flash in ¾ of an hour?
10. If point P is on line segment AB, then which
of the following is always true?
(1) AP = PB (2) AP > PB (3) PB > AP (4)
AB > AP (5) AB > AP + PB
1. Answer:
30 days.
Explanation:
Before:
One day work = 1 / 20
One man’s one day work = 1 / ( 20 * 75)
Now:
No. Of workers = 50
One day work = 50 * 1 / ( 20 * 75)
The total no. of days required to complete the
work = (75 * 20) / 50 = 30
2. Answer:
0 %
Explanation:
Since 3x / 2 = x / (2 / 3)
3. Answer:
5.3 %
Explanation:
He sells 950 grams of pulses and gains 50 grams.
If he sells 100 grams of pulses then he will gain
(50 / 950) *100 = 5.26
4. Answer:
250 lines of codes
5. Answer:
7 days
Explanation:
The equation portraying the given problem is:
10 * x – 2 * (30 – x) = 216 where
x is the number of working days.
Solving this we get x = 23
Number of days he was absent was 7 (30-23) days.
6. Answer:
150 men.
Explanation:
One day’s work = 2 / (7 * 90)
One hour’s work = 2 / (7 * 90 * 8)
One man’s work = 2 / (7 * 90 * 8 * 75)
The remaining work (5/7) has to be completed
within 60 days, because the total number of days
allotted for the project is 150 days.
So we get the equation
(2 * 10 * x * 60) / (7 * 90 * 8 * 75) = 5/7 where
x is the number of men working after the 90th
day.We get x = 225
Since we have 75 men already, it is enough to
add only 150 men.
7. Answer:
(c) 1
Explanation:
a percent of b : (a/100) * b
b percent of a : (b/100) * a
a percent of b divided by b percent of a : ((a
/ 100 )*b) / (b/100) * a )) = 1
8. Answer:
Cost price of horse = Rs. 400 & the cost price
of cart = 200.
Explanation:-
Let x be the cost price of the horse and y be
the cost price of the cart.
In the first sale there is no loss or profit.
(i.e.) The loss obtained is equal to the gain.
Therefore (10/100) * x = (20/100) * y
X = 2 * y -----------------(1)
In the second sale, he lost Rs. 10. (i.e.) The
loss is greater than the profit by Rs. 10.
Therefore (5 / 100) * x = (5 / 100) * y + 10
-------(2)
Substituting (1) in (2) we get
(10 / 100) * y = (5 / 100) * y + 10
(5 / 100) * y = 10
y = 200
From (1) 2 * 200 = x = 400
9. Answer:
451 times.
Explanation:
There are 60 minutes in an hour.
In ¾ of an hour there are (60 * ¾)
minutes = 45 minutes.
In ¾ of an hour there are (60 * 45) seconds
= 2700 seconds.
Light flashed for every 6 seconds.
In 2700 seconds 2700/6 = 450 times.
The count start after the first flash, the light
will flashes 451 times in ¾ of an hour.
20. Answer:
(4)
Explanation:
P
A B
Since p is a point on the line segment AB, AB
> AP
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